09 Sept 2026•Go / Python / TypeScript•Easy

Transpose Matrix

Return the matrix formed by swapping every input row and column.

View original LeetCode question

Allocate a columns-by-rows result and copy each input cell to the coordinates with reversed indices.

complexity

O(rows * columns) time and O(rows * columns) output space.

solution files

Go transpose-matrix/solution.go
Python transpose-matrix/solution.py
TypeScript transpose-matrix/solution.ts

Solution files

Go•transpose-matrix/solution.go

package main

func transpose(matrix [][]int) [][]int {
	result := make([][]int, len(matrix[0]))
	for column := range result {
		result[column] = make([]int, len(matrix))
		for row := range matrix {
			result[column][row] = matrix[row][column]
		}
	}
	return result
}

Python•transpose-matrix/solution.py

class Solution:
    def transpose(self, matrix: list[list[int]]) -> list[list[int]]:
        return [list(column) for column in zip(*matrix)]

TypeScript•transpose-matrix/solution.ts

function transpose(matrix: number[][]): number[][] {
  return Array.from({ length: matrix[class="syntax-number">0].length }, (_, column) => matrix.map((row) => row[column]));
}