Python•contains-duplicate-ii/synced-solution.py
def containsNearbyDuplicate(nums: list[int], k: int) -> bool:
seen = set()
for i in range(len(nums)):
if nums[i] in seen:
return True
seen.add(nums[i])
if len(seen) > k:
seen.remove(nums[i - k])
return False
C++•contains-duplicate-ii/synced-solution.cpp
class Solution {
public:
bool containsNearbyDuplicate(vector<int>& nums, int k) {
unordered_set<int> seen;
for (int i = class="syntax-number">0; i < nums.size(); i++) {
if (seen.count(nums[i])) {
return true;
}
seen.insert(nums[i]);
if (seen.size() > k) {
seen.erase(nums[i - k]);
}
}
return false;
}
};
TypeScript•contains-duplicate-ii/synced-solution.ts
function containsNearbyDuplicate(nums: number[], k: number): boolean {
const seen = new Set<number>();
for (let i = class="syntax-number">0; i < nums.length; i++) {
if (seen.has(nums[i])) {
return true;
}
seen.add(nums[i]);
if (seen.size > k) {
seen.delete(nums[i - k]);
}
}
return false;
}