Python•binary-tree-inorder-traversal/synced-solution.py
class Solution:
def inorderTraversal(self, root: Optional[TreeNode]) -> List[int]:
res = []
def dfs(node):
if not node: return
dfs(node.left); res.append(node.val); dfs(node.right)
dfs(root)
return res
C++•binary-tree-inorder-traversal/synced-solution.cpp
class Solution {
public:
vector<int> inorderTraversal(TreeNode* root) {
vector<int> res;
function<void(TreeNode*)> dfs = [&](TreeNode* node) {
if (!node) return;
dfs(node->left); res.push_back(node->val); dfs(node->right);
};
dfs(root);
return res;
}
};
TypeScript•binary-tree-inorder-traversal/synced-solution.ts
function inorderTraversal(root: TreeNode | null): number[] {
const res: number[] = [];
const dfs = (node: TreeNode | null) => {
if (!node) return;
dfs(node.left); res.push(node.val); dfs(node.right);
};
dfs(root);
return res;
}