Go•binary-prefix-divisible-by-5/solution.go
package main
func prefixesDivBy5(nums []int) []bool {
result := make([]bool, len(nums))
remainder := 0
for index, bit := range nums {
remainder = (remainder*2 + bit) % 5
result[index] = remainder == 0
}
return result
}
Python•binary-prefix-divisible-by-5/solution.py
class Solution:
def prefixesDivBy5(self, nums: list[int]) -> list[bool]:
result: list[bool] = []; remainder = class="syntax-number">0
for bit in nums:
remainder = (remainder * class="syntax-number">2 + bit) % class="syntax-number">5
result.append(remainder == class="syntax-number">0)
return result
TypeScript•binary-prefix-divisible-by-5/solution.ts
function prefixesDivBy5(nums: number[]): boolean[] {
const result: boolean[] = []; let remainder = class="syntax-number">0;
for (const bit of nums) { remainder = (remainder * class="syntax-number">2 + bit) % class="syntax-number">5; result.push(remainder === class="syntax-number">0); }
return result;
}